What the Theorem Says
When you divide any polynomial f(x) by a linear factor (x - a), you get a quotient and a remainder. That remainder is always a constant, and it equals f(a). So instead of doing the full division, you substitute a into the polynomial directly.
Remainder = f(a)
Why It Works
The polynomial division identity says f(x) = (x - a) * q(x) + r, where q(x) is the quotient and r is the remainder. If you substitute x = a, the first term becomes zero because (a - a) = 0. That leaves f(a) = r, so the remainder is f(a).
Worked Example 1
Find the remainder when f(x) = x³ - 4x² + x + 6 is divided by (x - 2).
Calculate f(2):
f(2) = 8 - 16 + 2 + 6
f(2) = 0
Remainder = 0
A remainder of 0 means (x - 2) is a factor. Checking: x³ - 4x² + x + 6 = (x - 2)(x² - 2x - 3).
Worked Example 2
Find the remainder when f(x) = 2x³ + 3x² - x + 5 is divided by (x + 1). Note that (x + 1) = (x - (-1)), so a = -1.
Calculate f(-1):
f(-1) = 2(-1) + 3(1) + 1 + 5
f(-1) = -2 + 3 + 1 + 5
f(-1) = 7
Remainder = 7
Connection to the Factor Theorem
The Factor Theorem follows directly from the Remainder Theorem. It says (x - a) is a factor of f(x) if and only if f(a) = 0. When the remainder is zero, the divisor goes in evenly, making it a factor.
This is useful for factoring higher-degree polynomials. Test candidate values by evaluating the polynomial at those points. If the result is zero, you found a factor.
Practical Uses
- Checking roots: Quickly test whether a given value is a root without full factoring.
- Faster divisions: Skip long division when you only need the remainder.
- Finding factors: Combined with the Factor Theorem, it helps break down complex polynomials.
- Number theory: The idea mirrors modular arithmetic and appears in computer science.
When It Does Not Apply
The Remainder Theorem only works when dividing by a linear binomial (x - a). If the divisor is quadratic or higher degree, you need long division or synthetic division instead. The remainder in those cases is not simply f(a).